cos2x的公式为:cos2x = (cosx)² - (sinx)² = 2(cosx)² - 1 = 1 - 2(sinx)²
公式推导过程基于余弦加法公式余弦加法公式为:cos(A + B) = cosA·cosB - sinA·sinB令 A = B = x,则:cos2x = cos(x + x) = cosx·cosx - sinx·sinx = (cosx)² - (sinx)²
转换为仅含cosx的表达式利用三角恒等式 (sinx)² = 1 - (cosx)²,代入上式:cos2x = (cosx)² - [1 - (cosx)²] = 2(cosx)² - 1
转换为仅含sinx的表达式利用三角恒等式 (cosx)² = 1 - (sinx)²,代入原始推导结果:cos2x = [1 - (sinx)²] - (sinx)² = 1 - 2(sinx)²
利用余弦加法公式cos3x = cos(2x + x) = cos2x·cosx - sin2x·sinx
代入倍角公式
cos2x = 2(cosx)² - 1
sin2x = 2sinx·cosx代入后得:cos3x = [2(cosx)² - 1]·cosx - [2sinx·cosx]·sinx
展开并简化cos3x = 2(cosx)³ - cosx - 2(sinx)²·cosx再次利用 (sinx)² = 1 - (cosx)²,替换 (sinx)²:cos3x = 2(cosx)³ - cosx - 2[1 - (cosx)²]·cosx= 2(cosx)³ - cosx - 2cosx + 2(cosx)³= 4(cosx)³ - 3cosx
最终结果:cos3x = 4(cosx)³ - 3cosx
总结