如果n为正整数,
则无解,
方法如下图所示,
请作参考,
祝学习愉快:
依据题意列式计算如下:
(7n-3)n-158=0
7n²-3n-158=0
△=(-3)²-4×7×(-158)
=9+4424
=4433>0
方程有二实数根,
n1=(3+√4433)/14
n2=(3-√4433)/14
7n^2-3n-158=0
(√7n)^2-3n+(3√7/14)^2-(3√7/14)^2-158=0
(√7n-3√7/14)^2-63/196-158=0
(√7n-3√7/14)^2-63/196-158x196/196=0
(√7n-3√7/14)^2-31031/196=0
√7n-3√7/14=±√(31031/196)
n=[3√7/14±√(31031/196)]/√7
n=[3√7/14±√(7x4433/196)]√7
n=3/14±√(4433/196)
n1=3/14+√(4433/196)
=(3+√4433)/14
n2=3/14-√(4433/196)
=(3-√4433)/14
(7n-3)n-158=0
7n²-3n-158=0
n=[3±√(3²+4×7×158)]/(2×7)
=(3±√4433)/14